A rigid rectangular loop of 1500 turns, which measures 0.15 m by 0.45 m, carries

Question

A rigid rectangular loop of 1500 turns, which measures 0.15 m by 0.45 m, carries a current of 0. 15A, as shown. A uniform external magnetic field of magnitude 0.23 T in the negative x- direction is present. Segment CD is in the x-z plane and forms a 35 degree angle with the z-axis, as shown. An external torque applied to the loop keeps it in static equilibrium. The magnitude of the external torque is closest to: a. 0.11 N middot m b. 4.8 N middot m c. 37 N middot m d. 2.0 N middot m e 54 N middot m

Explanation / Answer

Torque=magnetic moment*B*sin(theta)

Where theta is angle between B and magnetic moment

Magnetic moment=number of turn*i*area

Theta=55+90=145 degree

So we got torque=2 Nm

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