the formula on my graph is y=5.2689x^2 - 11.552x + 6.9833 I\'m not sure how it w

Question

the formula on my graph is y=5.2689x^2 -   11.552x + 6.9833
I'm not sure how it wants me to plug in each formula. I'm very confused. Thank you .

1. The table is the measured of the Position vs Time given in the following table. The variable is the time (x-axis) and obeys the equation positioa of a rock as it all: fom the top of a very high dliff Using Excel to make a plet dependent variable is the pesition (y-axis) and the independent y-1/2gt2. MeasurementTime ) Position () 0.0 5.0 0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 46 82 130 180 250 330 420 10 1. Right cick on a data point in the graph and add a "Tend line" Select a polysomal of order even by (1 2) This is a parabolic equation and deseribes an object falling under coastant acceleration The equation (1.1) that gives the position of the rock ia also a quadratic equation of the same form. Compare the two equations and determine the coesponding symbol in the theoretical equation (1.1) 15 pts

Explanation / Answer

the formula acheived from the graph is
y = 5.2689x^2 - 11.552x + 6.9833

now, this is a quadratic equation
comparing it with the kinematic equation
s = so + ut + 0.5at^2
where s is the final displacement
so is the initial displacement
u is the initial velocity
t is the time
a is the acceleration ( constant) of the body
so, comparing both we get

so = 6.9833 m
u = -11.552 m/s
a = 2*5.2689 = 10.5378 m/s/s

hence from equaiotn 1.1
g = 10.5378 m/s/s

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