You are standing in the middle of a large room listening to a cacaphony of sound

Question

You are standing in the middle of a large room listening to a cacaphony of sounds. Rank the intensity level of the sounds from each source (1 = loudest, 2 = next loudest,...) Consider all objects to be right next to you. (Remember that if you have a tie, you skip some ranks.) If two values are within 0.1 dB from each other, consider them to be the same. Two buzzers each producing a sound with intensity level of 56dB. Ten buzzers each producing a sound with intensity level of 52dB. An object emitting a sound with an intensity of 60dB. One hundred buzzers each producing a sound with intensity level of 43dB.

Explanation / Answer

First we have to understood that
n times louder is equal to = 10Log10(n) dB louder
(1) two buzzer each producing sound of 56 dB .
Hence the net intensity of sound will be = 56 + 10Log10(2) = 59 dB
(2) ten buzzers producing sound of 52 dB
= 52 + 10Log10(10) = 62 dB
(3) An object emitting a sound of 60 dB .
Hence net sound intensity = 60 dB
(4) 100 buzzers are producing sound of 43 dB
net intensity = 43 + 10Log10(100) = 63 dB
hence the ranking will be 4 ,2, 3,1

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