three resistors, 37 omega, 55 omega and 110 omega are connected in series and a

Question

three resistors, 37 omega, 55 omega and 110 omega are connected in series and a 0.53 A current passes through them. what are (a) the equivalent resistance and (b) the potential difference across this equivalent resistance three resistors, 37 omega, 55 omega and 110 omega are connected in series and a 0.53 A current passes through them. what are (a) the equivalent resistance and (b) the potential difference across this equivalent resistance three resistors, 37 omega, 55 omega and 110 omega are connected in series and a 0.53 A current passes through them. what are (a) the equivalent resistance and (b) the potential difference across this equivalent resistance

Explanation / Answer

As the resistors are in series, their equivalent resistance is algebraic sum of them.

Given:

R1 = 37 omega

R2= 55 omega

R3 = 110 omega

so equivalent resistance = R1 +R2 +R3 = 37 +55+110 = 202 omega

potential diffrence = current x equivalent resistance

=0.53 x 202 = 107.06 V

ALL THE BEST IN THE COURSE WORK

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