this will be the second time i have to ask this question to chegg. the last pers

Q: this will be the second time i have to ask this question to chegg. the last pers

L=I*w = (mL^2/12)*(w) = (0.7*2^2/12)*(120*2*pi/60) = 2.932 Kg-m^2/s

ID: 1290592 • Letter: T

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this will be the second time i have to ask this question to chegg.

the last person answered it as follows but that is not correct on mastering physics.

any help?

"Angular momentum of the bar is L = mvr = m(omega/r) r = (7*10^-3 kg)(120 rpm)(2phi/60 s) =0.087 kg m^2/s" WRONG...

Problem 9.34 The 700 g bar is rotating as shown in (Figure 1). Part A What is the angular momentum of the bar about the axle? Express your answer to two significant figures and include the appropriate units. L = Value Units

Explanation / Answer

L=I*w = (mL^2/12)*(w) = (0.7*2^2/12)*(120*2*pi/60) = 2.932 Kg-m^2/s

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this will be the second time i have to ask this question to chegg. the last pers

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