this question is from discrete and combatinatoral mathematics . by grimaldi. i r
ID: 3145599 • Letter: T
Question
this question is from discrete and combatinatoral mathematics . by grimaldi.
i refered chegg solution and that's the contetns....
I can't understand that statements "The total num of paths of length 2 with starting vertex as 'a' can be given as 3 C 2...
why??
there're more than 3C2...
ex..
from vertex 'a'?
a - b - e
a - c - f
a - c- d
a - d - c
a - d - f
isn't it??
why 3C2 ??
I know that like below...
3 C 2 means " select two vertices from (b,c,d) with no ordering"
3C2 = 3 >> bc, bd, cd...
please answer why the answer 3C2 ... T_T..
(I'm not english, so I can't understand english expressions more.. so, please explain carefully... (detailed, precious description please :)
Thank you for reading :)
Explanation / Answer
Hi,
Let me put the above solution more precisely,
to count the total number of paths in the full graph, lets count all the paths that pass through this vertex,
for example via a:
d-a-c
c-a-b
b-a-c
b-a-d
that is we can choose 2 vertices either side of 'a' so that vertex a passed through them i.e 3C2
now, in the example you gave, if we count paths passing through for all vertices, we can be sure that all vertices will be covered since they one of them can start, pass and end on each one of the path.
hence the answer is 3C2+3C2+4C2+3C2+2C2+3C2=19
Thumbs up if this was helpful, otherwise let me know in comments
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