A truck of mass 2000 kg has a low speed head-on collision with a small car of ma

Question

A truck of mass 2000 kg has a low speed head-on collision with a small car of mats 900 kg. The initial velocity of the truck it 10 m/s and the car was moving at 12 m/s. The two vehicles become stuck together. Assuming no one has used the brakes yet, how fast will the combined truck/car system be moving just after the collision and in what direction? A bullet is fired upwards at a heavy block of mass 5kg. The bullet has an initial speed of 900 m/s, a mass of 0.02 kg, and becomes embedded in the wood. How high will the bullet/block system rise off the table after the collision? Steps: Use momentum conservation to determine the speed of the bullet/block after the collision Use energy conservation for the bullet/block after the collision to see how high it rises

Explanation / Answer

(1) ans

Given that

mass m1=2000 kg

mass m2=900 kg

initial velocity u1=10 m/s

initial velocity u2=12 m/s

basing on the concept of the collision

now we find the combained velocity after collision

m1u1+m2u2=(m1+m2)v

2000*10+900*12=(2000+900)v

velocity v=10.6 m/s

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(2) ans

Given that

mass m1=0.02 kg

initial speed of the bullet u1=900 m/s

mass m2=5 kg

initial speed of the block u2=0 m/s

now we find the high of block rises

m1u1+m2u2-[m1+m2](2gh)^1/2

0.02*900+5*0=[0.02+5]*(2*9.8*h)^1/2

3.6=(19.6h)^1/2

height h=3.6^2/19.6=0.7 m

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