Name: Part I: Multiple Choice, Short Answer, Short Calculation and Sketching (3

Question

Name: Part I: Multiple Choice, Short Answer, Short Calculation and Sketching (3 pts each) The sketch below shows equipotential lines in a region of two conductors held at 4 V and-6v The poteatial of each line is labeled in volts by the number in the box. Use the sketch for questions 1, 2 and 3. 1. Sketch 4 electric field lines, one line through each point (A, B, C and D). You may stop any line that leaves the diagram or reaches the surface of either conductor 2. At which point (A, B, C, or D) is the electric field the weakest? How do you know? 3. How much work is done by the electric field on a proton which moves from point C to point D? 4. An electron released from rest in an electric field will (a) Move along an equipotential line to a point of higher potential. (b) Move along an equipotential line to a point of lower potential. (c) Move perpendicular to the equipotential lines to a point of higher potential. (d) Move perpendicular to the equipotential lines to a point of lower potential. 5. Consider the circuit shown below all capacitors were initially uncharged. Which capacitor will store the most charge when the battery is connected? 12 V

Explanation / Answer

1. field lines are always perpendicular to the equipotential lines.

so draw line at each point perpendicular to the given line.

2. at Point A, electric field is weakest.

3. deltaV = VD - VC = 0 - (-4) = 4 Volt

Work done by electric field = - (1.6 x 10^-19) (4)

= - 6.4 x 10^-19 J

4. (d) Move perpendicular to the equipotential lines to a point of lower potential.

5. suppose there is some charge Q on 4uf then it will further get divided into 7uF and 2uF .

hence 4uF will store the most charge.

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