People Window Help 97% rsa- Mon 10:08 PM Ch 14 HW Part 2 Secure https://session.

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People Window Help 97% rsa- Mon 10:08 PM Ch 14 HW Part 2 Secure https://session.masteringphysics.com/myct/itemviewzassignmentProblem Ch.14 HW Pat2 Problem 14.34 https://session.masteringphysics.com/mettemiew?assignmentProblemiD.7859739 1 previous 4 of 10r ro blem 14.34 measured by Eath clocks. His speed of orbit was 8100/slative to E.... uring this time interval. Assume two dlocks wore syna One cosmonaut orbited Earth for 537 days, as space on Earth, and one went into with the cosmonaut while the other remained on Earth. You are interested in knowing by how much the clock readings disagree at the end of the dock rudngs disagee·tte end ofto 537 days. There av some problems with applying the equation Part A What information other than the cosmonauts speed reilaive to Earth might you need to know? Check all that apply The mass of the cosmonaut and his ship The cosmonaut's travel direction relative to the direction of the Earth rotation. O The instant of time when the cosmonaut starts traveling G Speed of the Earth relative to the Sun 2 The Submit Incorrect; Try Again; 5 attempts remaining Part B If you used the equation , 7Atpriprt, what disagreement between te docks would you ger? Apop At, 0.169 Submit Incorrect; Try Again; 4 attempts remaining

Explanation / Answer

(A) Speed of Earth relative to the sun

(B) Y = 1 / sqrt[1 - (v/c)^2]

Y = 1 / sqrt[1 - (8100/(3 x 10^8))^2]

Y = 1 / 0.9999999996

so moving clock will be slow by this time.

on earth, 537 days.
  
But on cosmanaut, t = 537 / Y

time diff = (537 x 24 x 3600s) - (0.999999996 x 537 x 24 x 3600 )

= 0.0169 sec

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