e Edit View History Bookmarks People Window Help 99% isa, Sun 2:30 PM Ch 12 HW P

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e Edit View History Bookmarks People Window Help 99% isa, Sun 2:30 PM Ch 12 HW Part 1 PassignmentProblemiD 785972588offsetsnext Secure | https://ses Ch 12 HW Part1 Torque and Rotational Acceleration e previous3of Torque and Rotational Acceleration Part C Learning Goal Now consider a similar situation, except that now the swing bar itself has inertia m Figure 2 Find the rotational acceleration a of the seesavw Express your answer in terms of some or all of the quantities m.,m,mr , as well as the acceleration To understand and apply the formula T Ia to rigid objects rotating about a fixed axis To find the acceleration a of a partide of inertia m, we use the equation of motion: Ftma, where Fat is the net force acting on the partide o due to gravity g Hints Tofind the rotational acceleration of a rigid object rotating about a fixed axis, we can use a similar formula: Tnet=la, where Tat='sthe net torun actng on the object and I is its rotational inertia In this problem, you will practice applying this formula to several situations involving rotational acceleration. In all of these situations, two objects of masses m and ma are attached to a seesaw. The seesaw is made of a bar that has length I and is piveted so that it is free to rotate in the vertical plane without friction Submit My Answers Give Up You are to find the rotational acceleration of the seesaw Part D in what direction will the seesaw rotate and what wia the sign or the rotational acceeraton be? The rotaton is in the clockwise direction and the rotational acceleration is positive. The rotation is in the clockwise direction and the rotational acceleration is negative hThe rotaton is in the counterclockwise direcion and the rotational acceleration is positive The rotation is in the courterciockwise direction and tho rotational acceleration is negative nl2 Submit My Answers Sen U Part E This question wil be shown aher you complede previous question(o)

Explanation / Answer

We will find the angular acceleration of the seesaw when it is set in motion from the horizontal position. There were other parts to this problem, which I figured out.

Part A

The seesaw is pivoted in the middle, and the mass of the swing bar is negligible. Acceleration due to gravity = (2*(m1-m2)*g)/((m1+m2)*l)

Part B

Now consider a similar situation, except that now the swing bar itself has mass mbar. So, since the inertia of the bar is 1/12*mbar*l^2,

Angular Acceleration = (g*(m1-m2))/(l/2*(mbar/3+m1+m2))

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