(dp/dt)_|| and (dp/dt) for an object of mass m = 10 kg are shown at time t in th
ID: 1629416 • Letter: #
Question
(dp/dt)_|| and (dp/dt) for an object of mass m = 10 kg are shown at time t in the figure below. At this instant of time, | (dp/dt)_|| | = 40 kg m/s^2, |(dp/dt) | = 42 kg m/s^2, and theta = 90 degrees. Using the numbered direction arrows shown, indicate (by number) which arrow best represents the direction of the quantities listed below. If the quantity has zero magnitude or if more information is needed to determine the direction, indicate using the corresponding number listed below. (a) p, the object's momentum. _____ (b) (F_net)_||, the component of F_net that is parallel to the object's velocity. _____ (c) (F_net), the component of F_net that is perpendicular to the object's velocity. _____ (d) F_gravity, the force of gravity acting on the object. _____ (e) a, the object's acceleration. _____ (f) dp/dt, the time rate of change of the object's momentum. _____ (g) v, the object's velocity _____Explanation / Answer
(a) Information about initial momentum is required to find the direction of final momentum from dp/dt
Hence,10
(b) (Fnet)|| = (dp/dt)||
Hence, 5
(c) (Fnet)perpen = (dp/dt)perpen
Hence, 3
(d) Force of gravity acts downwards.
Hence, 5
(e) Object's accelearation is parallel to the net force.
Hence, 4
(f) dp/dt = Fnet
Hence, 4
(g) Direction of velocity is same as that of its momentum. And more info is needed to find the direction of momentum..
Hence, 10
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