(d) For rays incident from the glass onto the air-glass surface,determine and ta
ID: 1748016 • Letter: #
Question
(d) For rays incident from the glass onto the air-glass surface,determine and tabulate the angles of reflection and refraction forall the angles of incidence at 10.0° intervals from 0 to90.0°. (Fill in the table below with the angles of reflectionand refraction for the given angles of incidence. If there is totalinternal reflection put a zero in the refraction column.) incidence reflection refraction 0° ° ° 10° °Your answer differs from the correct answerby 10% to 100%.° 20° ° ° 30° ° ° 40° °
Your answer differs from the correct answerby 10% to 100%.° 50° °
Your answer differs from the correct answerby orders of magnitude.° 60° °
Your answer differs from the correct answerby orders of magnitude.° 70° ° ° 80° ° ° 90° °
Your answer differs from the correct answerby orders of magnitude incidence reflection refraction 0° ° ° 10° °
Your answer differs from the correct answerby 10% to 100%.° 20° ° ° 30° ° ° 40° °
Your answer differs from the correct answerby 10% to 100%.° 50° °
Your answer differs from the correct answerby orders of magnitude.° 60° °
Your answer differs from the correct answerby orders of magnitude.° 70° ° ° 80° ° ° 90° °
Your answer differs from the correct answerby orders of magnitude
Explanation / Answer
for reflection angle of incidence i=angle of refraction r for refraction refractive index==sini/sinr so sinr=sini/ r= sin-1[sini/] for total internal reflection sinc=1/ but for glass =1.5 so sinc =1/1.5=>c=41.81degree hence after the angle of incidence 40degree there will be norefraction and all the rays will be reflected. let us consider one example take 30 degree if i=30degree r=30degree [angle of reflection] for refraction r= sin-1[sini/]=sin-1[sin30/1.5]=19.47degree simiraly solve in other cases.
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