Start the \"Buoyancy\" simulation. Click the Reset All button (the “Masses” read

Question

Start the "Buoyancy" simulation. Click the Reset All button (the “Masses” readout option will be checked), and set the fluid type to Oil. Note that there are two scales, one in the air and one scale sitting at the bottom of the pool: use both for the following measurements. Click and drag to move the brick around.

Given:
weight of the brick in air= 49 N
weight of the brick in the unknown oil= 26.51 N
initial volume of the pool of oil= 0.1 m^3
volume of pool + brick= 0.1025 m^3
volume of oil displaced= 0.0025 m^3

Please all the questions. Thank you very much.

1&2:

3&4:

5.

ntro Buoyancy Playground Abou... Blocks - Same Mass O Same Volume O Same Density 3.00 5.00 kg 5.00 kg 0.00 N 100.00 L Show Forces Gravity Buoyancy Contact Readouts 0.00 N Masses Fluid O oil O Water Reset Al Force Values

Explanation / Answer

Q6.  Archimedes, stating that any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant, force the magnitude of which is equal to the weight of the fluid displaced by the body.

let volume of brick is v1

volume of liquid displaced is v2

buyont force= p*V1*g

Weight of displaced liquid =p*V2*g

from Archimedes principle, p*V1*g = p*V2*g

so, V1=V2

Ans. option a) sama as volume of brick

Q. 7. Three force will act on brick at the botttom of the pool

1. buoyant force 2. normal force 3. weight

Q. 8. Only 2 force will act on brick on sclae

1. normal force 2. weight

Q9 Inside the pool,

Normal + buoyant = total weight

Normal = 26.51

Total weight = 49N

Buoyant force = 49-26.51 = 22.49N

10. V =volume of brick =0.0025 m3

density =p

Buoyant force = p*V*g = p *0.0025*9.81= 22.49

p = 917 Kg/m3

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