Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

WileyPLUS C Secure https:// /edugen/student/mainfr.un edugen.wileyplus.com Wiley

ID: 1627183 • Letter: W

Question

WileyPLUS C Secure https:// /edugen/student/mainfr.un edugen.wileyplus.com Wiley PLU St M Contact Us Wiley PLUS Halliday, Fundamentals of Physics, 10e Gen Physics W/Calculus (Ph 211, 212, 213) Home Read, Study & Practice Assignment Gradebook ORION Assignment open Assignment PULLSOREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 19, Problem 011 Homework 11 er 19 Problem DZ Your answer is partially correct. Try again. Chapter 19 Problem 027 Air that initially occupies 0.83 m3 at a gauge pressure of 54 kPa is expanded isothermally to a pressure of 101.3 kPa and then cooled at constant pressure until it reaches 033 its initial volume. Compute the work done by the air. (Gauge pressure is the difference between the actual pressure and atmospheric pressure.) 038 Number 1.1 Chapter 19 Problem 060 the tolerance is +/-2% 003 Click if you would like to Show Work for this question Open Show Work 011 Chapter 20 Problem 027 Chapter 20 Problem 037 LINK TO TEXT LINK TO SAMPLE PROBLEM Chapter 20 Problem 040 035 By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Review Results by Stu Question Attempts: 3 of 6 used SAVE FOR LATER. SUBMIT ANSWER Copyright 2000-2017 by John Wiley & Sons, c. or related companies. All rights reserved License Agreement l Priva Policy I 000-2017 John Wil Sons Inca All Rights Reserved. A Division of lohn Wile & Sons inca Version 4.22.3.5

Explanation / Answer

intial pressure

P1 = 54 + 101.3

P1 = 155.3 kPa

P1 = 155300 Pa

W1 = 155300 X 0.83 X ln ( 155300 / 101300 )

W1 = 55074.97 J

W2 = 0.83 X ( 101300 -155300 )

W2 = - 44280 J

W = W1 + W2

W = 10794 J

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote