Let the magnetic field produced by infinitesimal amount of current be given by t
ID: 1624350 • Letter: L
Question
Let the magnetic field produced by infinitesimal amount of current be given by the Biot-Savart Law: dB vector = mu_0/4 pi Idl vector/r^2 times r^and Let the magnetic force exerted on a correspondingly small amount of current by the magnetic field (produced in the manner described above) be F vector_B = Idl vector times B vector and let The direction of the vector produced by the "cross" multiplication of two vectors, If not otherwise adjudicated be indicated by The 'Right-Hand' Rule. Then L) Underneath a long straight current flowing to the right, in what direction does the magnetic field point? M) If a rightward-flowing current is placed into a magnetic field which itself is pointing into the board, in what direction will the current be forced? N) If a rod is pulled to the East along metal rails and the whole apparatus is submerged in a constant magnetic field, then the positive charges in the rod will begin to move north.Explanation / Answer
L) If wire is straight and long and current is flowing to right, the direction of vector dl in Biot-Savart law is also to the right. If we are measuring the B vector due to a current in wire element of length dl at any point at distance of r from the wire, dl X r is perpendicular to both dl and r . Now if consider vector r and vector l to lie in the plane of the computer screen, the vector B then is in direction perpendicularly into the computer screen.
Same result is obtained when we apply right hand rule. The magnetic fieldflows counter clockwise in reference to the direction of current flow.
M) F will be perpendicular to both wire length dl (current flowing to right) and direction B field ( which in to the screen). Force being cross product dl and B will be vertically up on the plane of screen.
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