Let t F be the Fahrenheit temperature, t C be the Celsius temperature, and T be
ID: 1627457 • Letter: L
Question
Let
tF be the Fahrenheit temperature,
tC be the Celsius temperature, and
T be the Kelvin temperature.
tF=1.8tC+32... TRUE
.tC=T273.15......TRUE
Therefore, tF=1.8T459.67 .............EASY ENOUGH
.Since we want the Fahrenheit and Kelvin values equal, that means tF=T
, so
T=1.8T459.67.....EASY
and
0.8T=459.67 HOW?........IVE SPENT A COUPLE HOURS I KNOW IM MISSING SOMETHING SIMPLE SPENT TOO MUCH TIME GOING TO TAKE A BREAK READ MY KIDS A STORY AND PUT THEM TO BED. BE AS DETAILED AS POSSIBLE PLEASE
.Therefore, T=459.67/0.8=574.5875
and we have
574.5875 °F = 574.5875 K (which is the same temperature as 301.4375 °C)......THIS IS CORRECT BUT HOW DID GET .8T=459.67?
HOW DO YOU GET .8T=459.67?????????........
Explanation / Answer
It's simple mathematics equation solver
T = 1.8 T - 459.67
T- 1.8T= -459.67
-0.8T= -459.67
0.8T= 459.67
T= 459.67/0.8 = 574.58
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