A converging lens has a focal length of 19.3 cm. Give the image distance and mag

Question

A converging lens has a focal length of 19.3 cm. Give the image distance and magnification for the following object distances, using the correct sign conventions. Select all options that correctly describe the image. If the image is located at infinity, enter "infinity" for the image distance and for the magnification, and select "no image is formed".

(a) object distance = 40.2 cm
image distance

A converging lens has a focal length of 19-3 om. Give the image distance and magnification for the following object distances, using the correct sign conventions. Select all options that correctly describe the image. If the image is located at infinity, enter "infinity" for the image distance and for the magnification, and select no inage is formed object dista 40.2 cm distance magnification side of lens opposite the object e no image is formed upright same side of lens as the object inverted b) object dista 19.3 image distance magnification same side of lens as the object e upright inverted no image is formed virtual side of ens opposite the object object dista 10.3 image distance ponse you submitted has the wrong sign. magnification Your response differs from the correct answer by more than 10%. Double check your calculations.x no image is formed inverted a virtual upright real same side of lens as the object side of e opposite the object

Explanation / Answer

Using, 1/f = (1/o) + (1/i)

where, f is focal length

o is object distance

i is image distance

Magnification formula

m = -i/o

(a) 1/i = (1/f) - (1/o) = (1/19.3) - (1/40.2)

i = 37.17 cm

m = - 37.17/40.2 = -0.924

real, inverted, side of a lens opposite the object.

Real & inverted images are conventionally positive numbers, and they lie on the opposite side of the lens. The negative magnification (m = - positive image size / object size) indicates that the image is real and inverted.

(b) Object is located at the focal length, then no image is formmed because the refracted rays neither converge nor diverge. After refracting, the light rays are traveling parallel to each other and cannot produce an image.

(c) 1/i = (1/19.3) - (1/10.3)

i = - 22.12 cm

m = -(-22.12)/10.3 = 2.14

virtual, upright, and same side of a lens as the object

Virtual & upright images are conventionally negative numbers, and they lie on the same side of the lens. The positive magnification (m = - negative image size / object size) indicates that the image is virtual and upright.

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