A cylindrical pulley of mass m and radius R spins under the influence of two ten

Question

A cylindrical pulley of mass m and radius R spins under the influence of two tension forces T_1 and T_2 in the string as shown in the figure below. The Cartesian unit vectors are also shown. Knowing that T_1 > T_2 the angular acceleration vector alpha is equal to: a. 2(T_1 - T_2)/mR k b. T_1 - T_2/mR k c. 0 d. -2(T_1 - T_2)/2mK j e. -2(T_1 - T_2)/mR k A graph of position versus time for object oscillating at the free end of a horizontal spring is shown in the figure below. The point at which the object has maximum velocity and zero acceleration is a. A. b. B. c. C. d. D. e. E. A mass m = 2.0 kg is attached to a spring having an elastic constant k = 300 N/m as shown in the figure. The surfaces between the block and table are frictionless. The mass is displaced from its equilibrium position and released. Its frequency of oscillation (in Hz) will be approximately a. 12 b. 0.50 c. 0.01 d. 1.9 e. 0.08

Explanation / Answer

Here I am providing the solution for question no 20 as per chegg rule:

Since angular frequency of oscillation for such simple harmonic motion is given as

W= 2 * 3.14(K/m)^1/2

Hence frequency = (K/m)^1/2

f= (300/2)^1/2

f= 12.24

Hence f is nearly equal to 12 Hz

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