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A 1150-N uniform boom at = 68.0° to the vertical is supported by a cable at an a

ID: 1623075 • Letter: A

Question

A 1150-N uniform boom at = 68.0° to the vertical is supported by a cable at an angle = 58.0° to the horizontal as shown in the figure below. The boom is pivoted at the bottom, and an object of weight 2450 N hangs from its top.

7. 2/11 points I Previous Answers My Notes Ask Your Teacher A 1150-N uniform boom at p 68.0o to the vertical is supported by a cable at an angle 0 58.0 to the horizontal as shown in the figure below. The boom is pivoted at the bottom, and an object of weight 2450 N hangs from its top. (a) Find the tension in the support cable. 510.91 N X Your response differs from the correct answer by more than 10%. Double check your calculations. (b) Find the components of the reaction force exerted by the floor on the boom. horizontal component magnitude direction right vertical component magnitude direction upward

Explanation / Answer

Let's apply equation of torque at the botto m where boom touches the ground.

1150 ( L/2) sin( 90-68) + 2450 ( L) sin ( 90-68) = T sin 90 ( 3/4L)

575 sin (22) + 2450 sin (22) = T (3/4)

0.374 ( 3025) = T(0.75)

T = 1508.467 N apprx

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