Find the total energy (in MeV) liberated if one iron-58 nucleus were to be compl
ID: 1622135 • Letter: F
Question
Find the total energy (in MeV) liberated if one iron-58 nucleus were to be completely annihilated by one equivalent antimatter iron nucleus. Feel free to treat protons and neutrons as having one u of mass each. (For comparison purposes, one entire molecule of TNT detonating releases about 10 eV of energy.)Find the total energy (in MeV) liberated if one iron-58 nucleus were to be completely annihilated by one equivalent antimatter iron nucleus. Feel free to treat protons and neutrons as having one u of mass each. (For comparison purposes, one entire molecule of TNT detonating releases about 10 eV of energy.)
Find the total energy (in MeV) liberated if one iron-58 nucleus were to be completely annihilated by one equivalent antimatter iron nucleus. Feel free to treat protons and neutrons as having one u of mass each. (For comparison purposes, one entire molecule of TNT detonating releases about 10 eV of energy.)
Explanation / Answer
From the given question,
mass of iron nucleus= 58u= 58 x 1.67 x 10-27kg
by mass-energy equivalence formula
E=mc2
where E= Energy liberated
c= speed of light=3 x 108 m/s
m= mass of matter=58 x 1.67 x 10-27kg
E= 58 x 1.67 x 10-27 x(3 x 108)2
E=8.71 x 10-9 J
E=5.45 x 104 MeV
The total energy liberated is 5.45 x 104 MeV
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