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Find the total energy (in MeV) liberated if one iron-58 nucleus were to be compl

ID: 1620034 • Letter: F

Question

Find the total energy (in MeV) liberated if one iron-58 nucleus were to be completely annihilated by one equivalent antimatter iron nucleus. Feel free to treat protons and neutrons as having one u of mass each. (For comparison purposes, one entire molecule of TNT detonating releases about 10 eV of energy.)
Find the total energy (in MeV) liberated if one iron-58 nucleus were to be completely annihilated by one equivalent antimatter iron nucleus. Feel free to treat protons and neutrons as having one u of mass each. (For comparison purposes, one entire molecule of TNT detonating releases about 10 eV of energy.)
Find the total energy (in MeV) liberated if one iron-58 nucleus were to be completely annihilated by one equivalent antimatter iron nucleus. Feel free to treat protons and neutrons as having one u of mass each. (For comparison purposes, one entire molecule of TNT detonating releases about 10 eV of energy.)

Explanation / Answer

From the given question,

mass of iron nucleus= 58u= 58 x 1.67 x 10-27kg

by mass-energy equivalence formula

E=mc2

where E= Energy liberated

c= speed of light=3 x 108 m/s

m= mass of matter=58 x 1.67 x 10-27kg

E= 58 x 1.67 x 10-27 x(3 x 108)2

E=8.71 x 10-9 J

E=5.45 x 104 MeV

The total energy liberated is 5.45 x 104 MeV

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