ted ted ted. eted ated ted Class Management Help CH 19 HW Begin Date: 2/14/2017

Question

ted ted ted. eted ated ted Class Management Help CH 19 HW Begin Date: 2/14/2017 12:00:00 AM Due Date: 5/8/2017 11:59:00 PM End Date: 5/12/2017 12:00:00 AM charge q 6.2 HC sits at the origin. The coordinates of point A are (0, 5) m. The (5, 5) coordinates of point B are (520 m. The coordinates of point Care (5, 5) m. The (0,5) coordinates of point D are (5, -5 m. B (5,0) D (5, -5) Otheexpertta.com A 25% Part (a) How much work is done by the field in moving a proton from point A to point B in J? A 25% Part (b) How much work is done by the field in moving a proton from point C to point D in J? A 25% Part (c) How much work is done by the field in moving a proton from point C to point A in J? A 25% Part (d) How much work is done by the field in moving a proton from point D to point B in J? Grade Summary DB Deductions Potential 100% sino coso tano 7 9 Submissions Attempts remaining: 10 cotano asino acoso 5 6 (0% per attempt atan acotan0 s 1 2 3 detailed view cosh0 tanh00 cotanho PM

Explanation / Answer

a)

Va = (9 x 109) (6.2 x 10-6) /5 = 11160 Volts

Vb = (9 x 109) (6.2 x 10-6) /5 = 11160 Volts

Q = charge on proton = 1.6 x 10-19

Wab = Work done = Q (Vb - Va) = (1.6 x 10-19) (11160 - 11160) = 0 J

b)

since C and D are at same distance from charge at origin , hence Vc = Vd

Wcd = Work done = Q (Vd - Vc) = 0 J

c)

Vc = (9 x 109) (6.2 x 10-6) /sqrt(52 + 52) = 7891.31 Volts

Va = 11160 Volts

Wca = Work done = Q (Va - Vc) = (1.6 x 10-19) (11160 - 7891.31) = 5.23 x 10-16 J

d)

Vd = (9 x 109) (6.2 x 10-6) /sqrt(52 + 52) = 7891.31 Volts

Vb = 11160 Volts

Wdb = Work done = Q (Vb - Vd) = (1.6 x 10-19) (11160 - 7891.31) = 5.23 x 10-16 J

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.