te chegg Study | Guided S: ×MS Problem Sets-2017FA D Problem Set 8 2017.pdf Evan
ID: 547022 • Letter: T
Question
te chegg Study | Guided S: ×MS Problem Sets-2017FA D Problem Set 8 2017.pdf Evan T_ Xx × × 3. Consider the following mechanism of the hydrolysis of an acid chloride H OH + Hyo: a. (2 pts) Label I, Il, III, and IV as reactants, products, or intermediates. b. (3 pts) Circle what the enthalpy change be from I to Il would be. Remember to think about the relative stability of these species. C. (3 pts) Circle what the entropy change be from I to II would be. d. (3 pts) Considering your answers to parts b and c, do you think the reaction from I to Il would be spontaneous? Place a checkmark in the box next to your answer Yes, it would be spontaneous. No, it would not be spontaneous. It is impossible to know if it would be spontaneous without knowing the temperature at which this reaction is taking place e. (7 pts) Draw a reaction coordinate diagram for the entire transformation of I into IV (not just for the reaction of I to lI!). Your diagram should take into account The number of steps in this entire mechanism. The relative energies of the reactants, products, and intermediates. The first step is the rate-determining step .Labels on your axes. O Type here to search De 12:51 PM 10 24/2017Explanation / Answer
ANSWER FOR >>a) l is reactant.
ll & lll is intermediate.
lV is product.
>>>b)Enthalpy change in the step l to ll is deltaH=deltaH(bonds broken)-deltaH(bonds formed)
But in l to ll first there is C=O bonds bonds break and at the same time C-O bonds make.So in this process the change of energy is equal that is enthalpy does not change.
Therefore deltaH=0.
>>C) We know that if the number of reacting molecules is higher than the number of product molecules than the randomness is decreased that is entropy decreased and vise versa.Because entropy is measured by randomness of the molecules.
delta S=delta n(no. of product molecules)-delta n(no. of reacting molecules)
If delta S >0 then entropy is positive,
If delta S<0 then entropy is negative.
Here entropy is negative.
>>>d)It is impossible to know if it would be spontaneous without knowing the temperature at which reactions takesplace.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.