A 4/3 mu C point charge exerts an electrostatic force of 0.50 mN on a second poi

Question

A 4/3 mu C point charge exerts an electrostatic force of 0.50 mN on a second point charge of 2/3 mu/C. What is the distance between the changes? A. 4.0 times 10^-3 m B. 2.0 m C 2-8 m D. 4.0 m E0 7.1 m A -3.5-nC point charge is placed on the x axis at x = -1.7 m. and a +2.5-nC charge is placed on the y axis at y = 1.5 m. What is the magnitude of the electric field at the origin? A. 105 N/C B. 15 N/C C. 75 N/C 45 D. N/C E. 60 N/C Consider a spherical Gaussian surface of radius R centered at the origin. A charge Q is placed inside the sphere. To maximize the magnitude of the flux of the electric held through the Gaussian surface, the charge should be located. A at the origin. B at x = 0. y = 0. x = R/2. C. at x = R/2, y - 0. z = 0. D. at x = 0. y = R/2. z = 0. E. The charge can be located anywhere, since flux does not depend on the position of the charge as long as it is inside the sphere. Four current carrying wires are arranged in the corners of a square as shown in the picture. Which direction has the magnetic field in the center of the square? A. East B. South C. West D. North E. Zero

Explanation / Answer

4.

electrostatic force is given by:

F = kq1q2/R^2

R = sqrt (kq1q2/F)

Using the given values:

R = sqrt (9*10^9*(4*10^-6/3)*(2*10^-6/3)/(0.5*10^-3))

R = 4 m

Correct option is D.

5.

electric field is given by:

E = kQ/R^2

Ex = 9*10^9*3.5*10^-9/(1.7^2) = 10.9 N/C in -x axis

Ey = 9*10^9*2.5*10^-9/1.5^2 = 10 N/C in -y-axis

Magnitude of electric field will be:

E = sqrt (Ex^2 + Ey^2)

E = sqrt (10.9^2 + 10^2) = 14.79 N/C

Correct option is B

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