The pump in a water tower lifts water with a density of rho_w = 1.00 kg/liter fr
ID: 1618802 • Letter: T
Question
The pump in a water tower lifts water with a density of rho_w = 1.00 kg/liter from a filtered pool at the bottom of the tower up h_T = 21 m to the top of the tower. The water begins at rest in the pool and comes to rest at the top of the tower. The pump is 100% efficient in lifting the water, and it lifts a volume of V_w = 5.2 liters of water up the tower even second. The water tower sits on a hill that is T_e = 15 m above sea level. Let gravitational potential energy be zero at ground level. Calculate the power, P_p in Watts, of the pump. P_p = If the pump runs for 1.1 hours, calculate the increase in the potential energy, Delta U_w, in J, of the water in the tower. The water tower, when full, holds 10^6 liters of water. Calculate the gravitational potential energy of the water, U_w in J, of a full water tower relative to sea level.Explanation / Answer
Part (a)
The pump lifts water of volume Vw = 5.2 liters every second.
So, mass of water lifted every second by the pump is m = Vww = (5.2 liter) (1 kg/liter) = 5.2 kg
The work done by the tower in lifitng mass m of water by a height h = 21 m is,
WT = mgh = (5.2 kg)(9.8 m/s2)(21 m)
or, WT = 1070.16 J
This mass is lifted every second, so power used by the pump is,
Pp = WT/(1 s) = 1070.16 J/s = 1070.16 W
or, Pp = 1070.16 Watts
***************************************************************************************************
Part (b)
If the pump works for t = 1.1 hours = 3600X1.1 s = 3960 s, then energy used by the pump is,
E = Ppt = ( 1070.16 W)(3960 s)
or, E = 4.24X106 J
This energy is used to lift the water and the pump is 100% efficient, So total increase in potenrial energy of water is,
Uw = E
or, Uw = 4.24X106 J
***************************************************************************************************
Part (c)
Mass of full tank of water is m = (106 liter)(1 kg/liter) = 106 kg
The water is at a height of H = (21 + 15)m = 36 m relative to sea level
So gravitational potential energy of water relative to sea level is,
Uw = mgH = (106 kg)(9.8 m/s2)(36 m)
or, Uw = 3.53X108 J
***************************************************************************************************
This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification or correction, feel free to ask.....
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.