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What is conserved in an elastic collision that is not conserved in an inelastic

ID: 1618242 • Letter: W

Question

What is conserved in an elastic collision that is not conserved in an inelastic collision? a. Momentum b. Force c. Velocity d. Kinetic energy A nucleus at rest radioactively decays into an alpha particle and a smaller nucleus. The smaller nucleus has 65 times the mass of the alpha particle, which is ejected to the right with speed +v. In terms of v, what is the velocity of the nucleus? a. +v/65 b. -v/65 c. +65 v d. -65 v A fan blade speeds up at a rate of 3.4 rad/s^2 from rest to an angular speed of 3400.0 rad/s. How many revolutions does the fan go through before reaching this speed? a. 1700000.0 rev b. 10681415.0 rev c. 7649700.0 rev d. 500.0 rev For every equation we have learned for translational motion, is there an analogous equation for rotational motion? a. Yes b. No What is omega? a. Angular displacement b. Angular velocity c. Angular acceleration d. Angular force How much torque is required to accelerate a 3.0 kg cylinder with a radius R = 0.75 m at 5.4 rad/s^2 about its long axis? (I = 1/2 MR^2) a. 0.8 N middot m b. 4.6 N middot m c. 3.7 N middot m d. 2.1 N middot m

Explanation / Answer

32 ans

in elastic collsion the momentum and kinetic energy is conserved

in inelastic collision the momentum is conserved and kinetic energy is not conserved

so the correct option is D

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34 ans

Given that

angular acceleration=3.4 rad/s^2

angular speed w=3400 rad/s

now we find the angular displacement

3400^2=2*3.4*(angular displacement)

angular displacement=1700000 radians

the correct option is A

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35 ans

yes becasuse the rotational motion obtained from translational motion

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36 ans

the symbol W is called angular velocity

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37 ans

now we find the torque

torque =1/2*3*0.75^2*5.4=4.6 N.m

the correct option is B

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