What is conserved in an elastic collision that is not conserved in an inelastic
ID: 1569661 • Letter: W
Question
What is conserved in an elastic collision that is not conserved in an inelastic collision? a. Momentum b. Force c. Velocity d. Kinetic energy A nucleus at rest radioactively decays into an alpha particle and a smaller nucleus. The smaller nucleus has 65 times the mass of the alpha particle, which is ejected to the right with speed +v. In terms of v, what is the velocity of the nucleus? a. +v/65 b. -v/65 c. +65 v d. -65 v A fan blade speeds up at a rate of 3.4 rad/s^2 from rest to an angular speed of 3400.0 rad/s. How many revolutions does the fan go through before reaching this speed? a. 1700000.0 rev b. 10681415.0 rev c. 7649700.0 rev d. 500.0 rev For every equation we have learned for translational motion, is there an analogous equation for rotational motion? a. Yes b. No What is omega? a. Angular displacement b. Angular velocity c. Angular acceleration d. Angular force How much torque is required to accelerate a 3.0 kg cylinder with a radius R = 0.75 m at 5.4 rad/s^2 about its long axis? (I = 1/2 MR^2) a. 0.8 N middot m b. 4.6 N middot m c. 3.7 N middot m d. 2.1 N middot mExplanation / Answer
32 ans
in elastic collsion the momentum and kinetic energy is conserved
in inelastic collision the momentum is conserved and kinetic energy is not conserved
so the correct option is D
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34 ans
Given that
angular acceleration=3.4 rad/s^2
angular speed w=3400 rad/s
now we find the angular displacement
3400^2=2*3.4*(angular displacement)
angular displacement=1700000 radians
the correct option is A
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35 ans
yes becasuse the rotational motion obtained from translational motion
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36 ans
the symbol W is called angular velocity
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37 ans
now we find the torque
torque =1/2*3*0.75^2*5.4=4.6 N.m
the correct option is B
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