How are kilograms (kg) related to Joules (J), meters (m), and seconds (s)? kg =

Question

How are kilograms (kg) related to Joules (J), meters (m), and seconds (s)? kg = m^2/(J middot s^2) B) kg = J middot s^2/m^2 C) kg = J middot m^2 middot s^2 D) kg = J middot m^2/s^2. In the position vs, time graph below, an object moves along the x-axis in three step a stages from a time of 0.00s to a time of 60.0s. What is the average velocity for the full 60.0 second of the trip? upsilon vector = 0 25m/s in the positive indirection B) upsilon vector = 0.25m/s in the negative x-direction C) upsilon vector = 0.50m/s in the positive x-direction D) upsilon vector = = 0.50m/s in the- negative x-direction E) upsilon vector = 1.0m/s in the positive-direction F) upsilon vector = 1.0m/s in the negative x-direction G) upsilon vector = 2.0m/s in the positive x-direction H) upsilon vector = 2.0m/s in the negative x-direction.

Explanation / Answer

1)

W=F*d

W=ma*d

J=N*d

J= kg*m/s^2*m

J=kg*m^2/s^2

Simplifying,

kg=J*s^2/m^2

Thus option B is correct.

2)

Average velocity= average distance/total time

Vave=9d1+d2+d3)/t

Vave=(0+20-35)/60 = - 15/60 = -0.25m/s

Thus 0.25m/s in the negative x axis.

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