A thin film of glass, with an index of refraction of 1.50, is used to coat diamo

Question

A thin film of glass, with an index of refraction of 1.50, is used to coat diamond, which has an index of refraction of 2.40. The thickness of the thin film is 200. nm. Light, traveling through air, shines down along the normal to the film, as shown in the figure. (a) If we define the visible spectrum as extending from 400 nm to 700 nm (measured in air), for which wavelength in the visible spectrum (measured in air) does the film produce completely constructive interference for the reflected light? (b) In the limit that the thickness of the thin film approaches zero, would we expect constructive interference or destructive interference to take place for the reflected light? Note that "approaches zero" means that the film thickness is very small, much less than the wavelength of the light. Constructive, for all wavelengths Destructive, for all wavelengths Constructive for some wavelengths, and destructive for some wavelengths There is not enough information to answer this

Explanation / Answer

2 (mu) t= n lambda ( as cos r=1)

600 x 10^-9= lambda

in this formula put mu= 1.5, without using refractive index of diamond. Since you won't be needing refractive index of diamond.

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