1.) A wire carrying a 2-A current is placed at an angle of 60° with the respect
ID: 1615702 • Letter: 1
Question
1.) A wire carrying a 2-A current is placed at an angle of 60° with the respect to a magnetic field strength 0.2 T. If the length of the wire is 0.6 m, what is the magnitude of the magnetic force acting on the wire? Simplify your explanation.
2.) Now, a rectangular loop of wire, with dimension as shown in the figure below, carrying a 2-A current, placed in a magnetic field of 0.8 T. The rotates in the magnetic field and at one point makes 30° angle with the magnetic field. What is the magnitude of the torque acting on the wire? Simplify your explanation.
Explanation / Answer
1.
Magnetic force is given by:
F = i*LXB
F = i*L*B*sin theta
Using the given values:
F = 2*0.6*0.2*sin 60 deg = 0.208 N
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