STANDARD VIEW PRINTER VERS ON BACK NEXT Chapter 25, problem 015 Your answer is p
ID: 1614609 • Letter: S
Question
STANDARD VIEW PRINTER VERS ON BACK NEXT Chapter 25, problem 015 Your answer is partially correct. Try again. In the figure a 17 v battery is connected across capacitors of capacitances C1 Ce 3.0 uF and C3 Cs 2.0C 2.004 4.5 uF. What are (a) the equivalent capacitance Ceg of the capacitors and (b) the charge stored by Ceq? What are (c) V1 and (d) a1 of capacitor 1, (e) V2 and (f) q2 of capacitor 2, and (g) Va and (h) ga of capacitor 3? (a) Number e 3.1765 (b) Num (c) Numl (d) Num (e) Number (f) Num Unit (g) Numbe (h) Num Unit SHow HINT co TuroRIAL LINK TO SAMPLE PROBLE VIDEO HI LECTURE Question Attempts: 3 of 6 used SAVE FOR LATER SUBMIT ANSWER e 2000-2017 by Jahn wiey s sons, inc. or related companies. Ail rights reserved CopyrightExplanation / Answer
a)
C3 and C5 are in series and their combination is given as
C35 = C3 C5/(C3 + C5) = 4.5 x 4.5 /(4.5 + 4.5) = 2.25 uF
C4 , C35 and C2 are in parallel and their combination is given as
C2345 = C4 + C35 + C2 = (4.5/2) + 2.25 + (4.5/2) = 6.75 uF
C1 and C6 are in parallel and their combination is given as
C16 = C1 + C6 = 3 + 3 = 6 uF
C16 and C2345 are in series and their combination is given as
Ceq = C16 C2345 /(C16 + C2345 ) = 6.75 x 6 /(6.75 + 6)
Ceq = 3.2 uF
b)
V = 17
charge stored is given as
Qeq= Ceq V = (3.2) (17) = 54.4 uC
c)
V1 = Voltage across C16 = Qeq/C16 = 54.4/6 = 9.1 volts
d)
q1 = C1 V1 = (3) (9.1) = 27.3 uC
e)
V2 = Voltage across C2345 = Qeq/C2345 = 54.4/6.75 = 8.1 Volts
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