STA 2023-Summer 2018 Ref #4833 cS Homework: HW7 Score: 0.13 of 1 pt 24 of 30 (27
ID: 3370184 • Letter: S
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STA 2023-Summer 2018 Ref #4833 cS Homework: HW7 Score: 0.13 of 1 pt 24 of 30 (27 complete) HW Score: 71.53%, 21.46 of 30 pts &5.2.29 Question Help gives birth to one baby. This method is designed Assume that different groups of couples use a particular method of gender selection and each to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girt is 0.5. Assume that the groups consist of 42 couples parts (a) through (c) below. The value of the mean is ?, 21 (Type an integer or a decimal. Do not round) The value of the standard deviation is ? 32. (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are signiflcantly low or significantly higth Values of 14.6 girls or fewer are significantly low (Round to one decimal place as needed.) Values ofgirls or greater are significantty high (Round to one decimal place as needed.) Enter your answer in the answer box and then click Check Answer part e to searchExplanation / Answer
sOL:
n=42
p=1/2=0.5
mean=np
=42*1/2=21
mean=21
standard deviation=sqrt(npq)
=sqrt(42*0.5*0.5)
=3.24
standard deviation=3.2
Solutionb:
mean-2sd=21-2*3.2=14.6
values of 14.6 girls or fewer are significantly low
mean+2sd=21+2*3.2=27.4
values of 27.4 girls or fewer are significantly high
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