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ngEngineering MasteringComputerskience 12. Ch18 Mamemmmmor system of partides Go

ID: 1612453 • Letter: N

Question

ngEngineering MasteringComputerskience 12. Ch18 Mamemmmmor system of partides Google Chrome secure l https//session.masteringengineering.com/myct/itemview?assignmentProblemID-5609383&offset; next signed in as Ahmed Problem 18.11 previous 4 of 10 roblem 18.11 Part A The moment of inertia of the astronaut and If he is initially not rotating, and at t 0 he activates the maneuvenng unit about the axis through their center thruster until ho is rotating at 15 per second. through how of mass perpendicular to the page is 40 kg m many degrees has he rotated at t 10 s? A thruster can exert a force T 10 N For safety the control system of his maneuvering unit will not allow his angular velocity to exceed 15 per second Figure 1 or 1 Submit Continue

Explanation / Answer

I= 40 kg.m^, T = 10 N, d = 300 mm

w = 15 degrees/s , t =10s

torque = Td = I*alpha

10*0.3 = 40*alpha

alpha =0.075 rad/s^2

w = alpha*t

(15)(3.14/180) = 0.075*t

t = 3.49 s

theta1 = 0.5*alpha*t^2

= 0.6*(0.075)(3.49)^2

theta1 = 0.457 rad

After this time, the astronauts turns at the fixed rate. He rotated an additional angle given by

theta2 = wt = (15)(3.14/180)(10-3.49)

= 1.704 rad

The total rotation is then

theta = theta1+theta2

= (0.457 +1.704)(180/3.14) = 124 degrees