The next two problems are concerned with the experimental setup shown in the dia

Question

The next two problems are concerned with the experimental setup shown in the diagram. An upright, 1.0 cm high object is 10.0 cm to the left of the lens and a real image is formed 20.0 cm to the right of the lens. i. The focal length of the lens is closest to: A. +20.0 cm. B. +5.9 cm. C. +7.5cm. D. +15.0 cm. E. +6.7 cm. ii. The orientation and height of the image are closest to: A. inverted and 2.0 cm high. B. inverted and 3.0 cm high. C. upright and 2.0 cm high. D. upright and 3.0 cm high. E. upright and 2.5 cm high.

Explanation / Answer

for lens

object distance p = 10 cm

image distance q = 20 cm

from lens equation

1/p + 1/q = 1/f

1/10 + 1/20 = 1/f

focal length f = +6.7 cm <<<<------answer

OPTION (E)

===========================

magnification m = -q/p = -2

magnification m = size of the image/size of the object

size of the image/1 = 2

size of the image = 2

m is negative so the image is inverted

and size is 2cm

inverted and 2 cm high

option (A)

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