The next six questions are about the following situation: Four point charges are

Question

The next six questions are about the following situation:

Four point charges are arranged in the configuration below. Each grid unit is 1 m.

1)  What is the direction of the FORCE that the -2mC charge exerts on the 4mC at the origin?

+x-direction

+y-direction

-x-direction

-y-direction

the force is zero

2)  What is the magnitude of the FORCE that the -2mC charge exerts on the 4mC at the origin?

.0045 N

.0085 N

.0125 N

.0175 N

0 N

3)  What is the direction of the FORCE that the -2mC charge AND the +2mC exert on the 4mC at the origin?

+x-direction

+y-direction

-x-direction

-y-direction

the force is zero

4)  What is the magnitude of the FORCE that the -2mC charge AND the +2mC exert on the 4mC at the origin?

.0023 N

.0090 N

.015 N

.021 N

0 N

5)  Calculate the x-component of the net electric field at (0,2) due to the four charges shown.

Ex = 3.9 × 103 N/C

Ex = 1.6 × 103 N/C

Ex = -3.9 × 103 N/C

Ex = -1.6 × 103 N/C

Ex = 0 N/C

6)  Calculate the y-component of the net electric field at (0,2) due to the four charges shown.

Ey = -3.9 × 103 N/C

Ey = 8.1 × 103 N/C

Ey = 3.9 × 103 N/C

Ey = -8.1 × 103 N/C

Ey = 0 N/C

Explanation / Answer

1) Direction is [-x]
2) Using the Coulomb's Law
F = k.q1.q2 / r2 = 9 * 109 * [-2 * 10-6] * [+4 * 10-6]/ 42 = 0.0045 N
3) Net force on +4mC will be ZERO. This is because force from both the directions is of same magnitude but opposite direction. So, it will cancel out.
4) As said above F = 0 N.

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