A circular loop of radius 12 cm carries a current of 20. A. A second loop of rad

Question

A circular loop of radius 12 cm carries a current of 20. A. A second loop of radius 0.72 cm, having 70. turn and a current of 1.4 A, is at the center of the first loop. Assume that the planes of the two loops are at right angles and that the magnetic fields due to the larger loop is essentially uniform throughout the volume occupied by the smaller loop.
(a) What magnetic field magnitude does the larger loop create at its center?

(b) Calculate the torque magnitude that acts on the smaller loop?

Can you please help me for question 5?

Thank you

A circular loop of radius 12 cm carries a current of 20. A. A second loop of radius 0.72 cm, having 70. turn and a current of 1.4 A, is at the center of the first loop. Assume that the planes of the two loops are at right angles and that the magnetic fields due to the larger loop is essentially uniform throughout the volume occupied by the smaller (a) What magnetic field magnitude does the larger loop create at its center? 1104.72 mu T (b) Calculate the torque magnitude that acts on the smaller loop? 1.67e-06 Nm

Explanation / Answer

THE magnetic field due to larger wire is B= (muo * i)/2R

where muo is 4pi *10^-7

i is curren and R is radius

so

B = (4pi *10^-7 * 20)/(2 * 0.12)

B = 104.4 uT

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part B:

use the formula of torque T = i A B N sin theta

here theta = 90 degree

so

T = 70 * 1.4 * 3.14* 0.0072* 0.0072 * 1.04 *10^-4

T = 1.66 *10^-6 um

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