A circular hole, with a radius of 10 cm, is cut in the center of two aluminum pl

Question

A circular hole, with a radius of 10 cm, is cut in the center of two aluminum plates. The aluminum plates have different shapes, as shown in the figure below. The coefficient of linear expansion of aluminum is 2.4 times 10^-5 middot C^-1 If the temperature of each plate is increased by 20 degree C (an increase of about 36 degree F) above the starting temperature, then: The area of the hole in the square plate will increase more than the area of the hole in the circular plate. The area of the hole in the circular plate will increase more than the area of the hole in the square plate. The area of the hole in each plate will increase by the same amount. The area of the hole in each plate does not change.

Explanation / Answer

The formula for areal expansion is

del A= A (beta) del T

= A( 2 linear expansion) del T

for circular shape

del A = pi ( 0.1)^2 ( 2 (2.4* 10^-5) ( 20) = 3.0144* 10^-5 m^2

for square plate

del A = pi ( 0.1)^2 ( 2 (2.4* 10^-5) ( 20) = 3.0144* 10^-5 m^2

so the change in are of each plate is same irrespective of the shapes

so, the area of the hole in each plate will increase by the same amount

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.