A certain diffraction grating is described as having 600 lines/mm. what is the s

Question

A certain diffraction grating is described as having 600 lines/mm. what is the spacing between adjacent lines for this grating? A. 0.00167 m B. 0.0167 cm C. 1.67 times 10^6 m D. 167 times 10^4 m In a spectroscopy experiment, your determine a particular wavelength for a spectral line to be 656 nm. what is the energy of these photons of light in units of eV? (h = 4.14 times 10^11 eVxs) A. 3.03 times 10^-19 eV B. 1 .89 eV C. 0.0528 eV D. 1.89 times 10^-4 eV Which of the following statements is true about spectral lines produced by different elements? A. The photons are being emitted as electrons make transitions to higher energy levels. B. Since all atoms have at least one proton, all elemental spectra contain the same spectral line as hydrogen. C. Long wavelength photons come from transitions of electrons between energy levels with big differences. D. At room temperature without a voltage being applied, most atoms are in the ground state. In the spectral lines of mercury experiment, lines were seen that corresponded to transitions of electrons between atomic energy levels. Which of the following is true about the four colors closest to the light source? A. They represent order numbers 1-4 B. The all have order number 1. C. They all have order number 0. D. They all have order number 4. Complete the sentence so that it is true. In beta minus decay, A. an electron decays into another particle. B. a proton is ejected from the nucleus. D. an electron is ejected from the nucleus. If a radioactive sample had an activity of 1000 cpm, and the half-life of the isotope were 30 minutes, what would be the activity of the sample after 2 hours? A. 63 cpm B. 33 cpm C. 250 cpm D. 125 cpm In the equation that describes radioactive decay, N = N_0 e^-lambda t, the variable lambda is A. the wavelength of the radioactive particle. B. the decay constant.

Explanation / Answer

here,

41)

for the diffrecation grating

number of lines per mm , n = 600 lines per mm

n = 600 000 lines per m

so ,

the spacing between the adjacent lines , d = 1/n

d = 1/600 000 m

d = 1.67 * 10^-6 m

so the correct answer is D) 1.67 * 10^-6 m

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