1. Calculate the specific heat of the metal powder c . c = J/kg-K Specific heats

Question

1. Calculate the specific heat of the metal powder c.

c =  J/kg-K

Specific heats of metals Tables list the specific heat of many substances, and these values can be in terms of the heat capacity per mass, per mole or per atom of a given substance. There is a fundamental issue here, known for over 150 years: when the specific heat ofmany pure substances in the solid state at room temperature (copper, gold, aluminum, lead) is expressed per mole of substance it is found that all have nearly the same specific heat: Cin 3R, where R 8.31 Jlmol-K is the "gas constant." Early successes of classical statistical and solid state physics dealt with an explanation of this phenomenon, which is called "the law of corresponding states." Another example of this law is that all monatomic gases have the same specific heat per mole: G/2)R. 600 g of an unknown metal powder at T 84 °C are dropped into a calorimeter containing 70 g of water at 5 °C. The final equilibrium temperature is measured to be 21.5 C. i Calculate the specific heat of the metal powder c. J/kg-K. 2. From the table of specific heats shown here (from Walker, identify the metal. Substance specific heat Atomic weight J/kg-K) g/mol 4186 Water 18.0 Beryllium 1820 9.0 Aluminum 900 27.0 Silicon 703 28.1 448 55.8 ron Copper 387 63.5 Silver 234 107.9 197.0 Gold 129 Lead 128 207.22 Water Beryllium Aluminum Silicon Copper o Silver Gold Lead

Explanation / Answer

1 . Assuming no heat loss then

heat absorbed by water = heat released by metal

70 x 4186 x (21.5 - 5) = 600 x C x (84 - 21.5)

C = 4834830 / 37500

C = 0.129 J/kg - K

2. Metal is Gold.

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