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Print calculator Periodic Table Question 4 of 4 Map Sapling Learning A round pip

ID: 1606223 • Letter: P

Question

Print calculator Periodic Table Question 4 of 4 Map Sapling Learning A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead the pipe's diameter is 53.9 cm (0.539 m) and the flow speed of the petroleum is 13.1 m/s. At the refinery the petroleum flows at 5.23 m/s. What is the volume flow rate of the petroleum along the pipe and what is the pipe's diameter at the refinery? Volume flow rate: Number m /s Diameter: Number cm O Previous 2 Check Answer Next Exit Give Up & View Solution

Explanation / Answer

equation of continuity


volume flow rate remains constant at any point in fluid flow

volume flow rate V = Area*velociy = A1*v1


A1 = pi*d1^2/4


d1 = diameter at wellhead


volume flow rate V = pi*(0.539^2/4)*13.1 = 2.99 m^3/s    <<<<-------------answer


=====================


volume flow rate at well head = volume flow rate at refinery


V = A2*v2 = pi*d2^2/4*v2


d2 = diameter at refinery


v2 = speed at refinery


2.99 = pi*d2^2/4*5.23


diameter d2= 0.853 m = 85.3 cm <<<<-------------answer

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