A conducting rod of length L = 0.015 m is lying on a rectangular wire as shown i

Question

A conducting rod of length L = 0.015 m is lying on a rectangular wire as shown in the figure. A constant magnetic field with magnitude B = 0.45 T pointing into the paper is in the region. The rod is pulled to the right by an external force, and moves with constant speed v = 0.065 m/s. The resistance in the wire is R =180 Ohm. L = 0.015 m B = 0.45 T v = 0.065 m/s R = 180 Ohm Express the magnitude of the magnetic flux going through the loop. phi, in terms of B. a and L. Express the change in the magnetic flux, Delta Phi. in terms B, L, v and delta t. Express the magnitude of the avenge emf induced in the loop. elementof. in terms of B, L, v. Calculate the emf. in volts. Express the current induced in the loop. I. in terms of elementof and R. Calculate the value of I. in amperes.

Explanation / Answer

part a)

The magnetic flux going throughthe loop is

phi = B * A = B * a * L

phi = B * a * L

part b)

change in flux is final - initial

Delta(phi) = (B * L * (a + (v * delta(t)) - ( B * a * L)

Delta (phi) = B * L * v * delta(t)

part c)

induced emf = v * B * L

part d)

e = 0.065 * 0.45 * 0.015

e = 4.38 * 10^-4 V

part e)

current I = e / R

part f)

I = 4.38 * 10^-4 / 180

I = 2.43 * 10^-6 A

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