A 120 g ball moving to the right at 4.4 m/s catches up and collides with a 440 g

Question

A 120 g ball moving to the right at 4.4 m/s catches up and collides with a 440 g ball that is moving to the right at 1.2 m/s .

a.) If the collision is perfectly elastic, what is the speed of the 120 g ball after the collision?

b.) If the collision is perfectly elastic, what is the direction of motion of the 120 g ball after the collision?

c.) If the collision is perfectly elastic, what is the speed of the 440 g ball after the collision?

d.) If the collision is perfectly elastic, what is the direction of motion of the 440 g ball after the collision?

Explanation / Answer

(A) for elastic collision,

4.4 - 1.2 = v2 - v1

-v1 + v2 = 3.2

Applying momentum conservation,

120 x 4.4 - 440 x 1.2 = 120v1 + 440v2

120v1 + 440v2 = 0

Solving,

v1 = -88/35 = - 2.51 m/s and v2 = 24/25 = 0.69 m/s

Ans: 2.51 m/s to the left.

(B) to the left

(C) 0.69 m/s

(D) to the right

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