please help with part c An object with a charge of -2.7 mu C and a mass of 4.7 t

Question

please help with part c

An object with a charge of -2.7 mu C and a mass of 4.7 times 10^-2 kg experiences an upward electric force, due to a uniform electric field, equal in magnitude to its weight. Find the magnitude of the electric field. Express your answer using two significant figures. E = 1.7 times 10^5 N/C Find the direction of the electric field. upward downward to the left to the right If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration. Express your answer using three significant figures.

Explanation / Answer

Electric force, due to a uniform electric field, equal in magnitude to its weight.

|qE| = |mg|

E = mg/q

Assuming the object is on the Earth,

E = 4.7x10² x 9.8 / (2.7x10) = 17.059 x 10 N/C

Given the electrical force acts upwards (+j, say). From the equation

F = qE

it can be deduced that for a negatively charged (q) particle, the force acts in the direction opposite to that of the field. The electric field is acting vertically downards (-j).

When the charge is doubled,

F = qE = ( 2 x -2.7x10)(-j 17.059 x 10) = 0.9212j N

That is, 0.9212N in vertically upward direction.

Part C. When charge becomes double

Fnet = 2*q*E - m*g

m*a = 2*q*E - m*g

= 2*(m*g) - m*g

= g

= 9.8 m/s^2

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