A 11-cm-diameter circular loop of wire is placed in a 0.80-magnetic field. Part
ID: 1600883 • Letter: A
Question
A 11-cm-diameter circular loop of wire is placed in a 0.80-magnetic field. Part A When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop? Express your answer to two significant figures and include the appropriate units. The plane of the loop is rotated until it makes a 43 angle with the field lines. What is the angle in the equation for this situation? Express your answer using two significant figures. Part C What is the magnetic flux through the loop at this angle? Express your answer to two significant figures and include the appropriate units.
Explanation / Answer
given
d = 11 cm = 0.11 m
B = 0.80 T
A) magnetic flux through the loop = A*B*cos(theta) (here theta is the angle between normal to the loop and B)
= (pi*d^2/4)*B*cos(0)
= (pi*0.11^2/4)*0.8
= 7.6*10^-3 T.m^2 or weber
B) theta = 90 - 43
= 47 degrees
C) magnetic flux through the loop = A*B*cos(theta) (here theta is the angle between normal to the loop and B)
= (pi*d^2/4)*B*cos(47)
= (pi*0.11^2/4)*0.8*cos(47)
= 5.2*10^-3 T.m^2 or weber
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