As a rocket is accelerating vertically upward at 9.3 m/s^2 near the Earth\'s sur

Question

As a rocket is accelerating vertically upward at 9.3 m/s^2 near the Earth's surface, it releases a projectile, immediately after release the acceleration (in m/s^2) of the projectile is: A) 9.8 up B) 9.8 down C) 9.3 down D) 9.3 up E) none of the above The motion of a particle is described in the velocity versus time graph shown in the figure. We can say that its speed: A) increases B) decreases C) decreases and then increases D) increases and then decreases E) none of the above A pilot drops a package from a plane flying horizontally at a constant speed. Neglecting air resistance, when the package hits the ground the horizontal location of the plane will A) be behind the package B) be in front of the package C) depend of the speed of the plane when package was released D) be over the package E) none of the above A satellite orbits the earth a distance of 21.35 times 10^6 m above the planet's surface and takes 6.65 hours for each revolution about the earth. The acceleration of this satellite is closest to A) 1.11 m/s^2 B) 0.870 m/s^2 C) 3.01 m/s^2 D) 2.04 m/s^2 E) 1.47 m/s^2 For a particle in uniform circular motion A) Acceleration has constant magnitude but varying direction B) Velocity is constant in magnitude and direction C) Acceleration is constant in magnitude and direction D) Velocity and acceleration are perpendicular only at the top of the circle E) Velocity and acceleration are always parallel

Explanation / Answer

5) HERE projectile is in freely falling so a = 9.3 m/s^2 down

6) decreases and then increases

7) be over the package

8) a = v^2/r

v = 2pir/T

9) in uniform circular motion speed remains constant and acceleration is also constant in magnitude and direction. it is always acting towards the center.

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