Given a velocity selector and a mass spectrometer with magnetic field of 4 T. If

Question

Given a velocity selector and a mass spectrometer with magnetic field of 4 T. If the electric field between the plates in the velocity selector is 200 V/m and the radius of the doubly charged ion's orbit is 0.10 mm, find the mass of the ion.
Please show all work. Given a velocity selector and a mass spectrometer with magnetic field of 4 T. If the electric field between the plates in the velocity selector is 200 V/m and the radius of the doubly charged ion's orbit is 0.10 mm, find the mass of the ion.
Please show all work.
Please show all work.

Explanation / Answer

B = magnetic field = 4 T

E = electric field = 200 V/m

v = velocity of ion

r = radius = 0.1 mm = 1 x 10-4 m

q = charge on the ion = 2 x 1.6 x 10-19

inside the velocity -seclector

magnetic force on ion = electric force by electric field on the ion

q v B = qE

v = E/B = 200/4 = 50 m/s

in the spectrometer

magnetic force provides the necessary centripetal force to move in circle

hence magnetic force = centripetal force

qvB = mv2 /r

m = qBr/v

m = (2 x 1.6 x 10-19) (4) (4 x 10-4)/50

m = 1.024 x 10-23 kg

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.