Now we\'ll apply the thin-lens equation to the eye. When light enters your eye,

ID: 1600263 • Letter: N

Question

Now we'll apply the thin-lens equation to the eye. When light enters your eye, most of the focusing happens at the interface between the air and the comes (the outermost element of the eye). The eye also has a double-convex lens, lying behind the comes, that completes the job of forming an image on the retina. (The lens also enables us to shift our distance of focus; it gets rounder for near vision and father for far vision.) The crystalline lens has an index of refraction of about 1.40. (a) For the lens shown (Figure 1), find the focal length, (b) If you could consider this lens in isolation from the rest of the eye, what would the image distances be for an object 0.20 m in front of this ions? SETUP The center of curvature of first surface of the lens is on the outgoing side, so R_1 = + 6.0 mm. The center of curvature for the second surface is not on the outgoing side, so R_2 = -5.5 mm. We solve for f and then use the result in the thin-lens equation. Using the equation below, we find that 1/f = (n - 1)(1/R_1 - 1/R_2) 1/f = (1.40 - 1)(1/+6.0 mm - 1/-5.5 mm) f = 7.2 mm The object distance is d_n = 0.20 m = 200 mm. Using the thin-lens equation, 1/f - 1/d_ + i/d_i, we obtain 1/200 mm + 1/d_f = 1/7.2 mm d_f = 7.5 mm The image is slightly farther from the lens than it would be for an infinity distant object. As expected for a converging lens, the focal length is positive Suppose that to observe an object that is 5.93 m away, the lens in your eye flattens out so that it acts like the crystalline lens in the example, excepts with radii of curvature of C_1 = 10.0 mm and C_2 = 9.10 mm. How far behind the lens would the image form in this cases? Express your answer to three significant figures and pay attention to units.

Explanation / Answer

using the equstion:

1/f = (n-1)(1/R1 - 1/R2) = (1.40 - 1) [1/5.0mm - 1/-4.55mm]

or, f = 5.955 mm

again using the formula:

1/do + 1/di = 1/f

or, 1/5930 + 1/di = 1/5.955

or, di = 5.961 mm ..........................................ans

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Now we\'ll apply the thin-lens equation to the eye. When light enters your eye,

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