Given an electron ejected by the sun, how much force would it feel as it approac

Question

Given an electron ejected by the sun, how much force would it feel as it approached the Earth at the equator? Assume the electron's speed to be 90% the speed of light, approaches at the magnetic equator, and the Earth's magnetic field strength to be 20 mT when the electron encounters it. a) What initial direction would it travel (N, S, E, W)? b) How about if it approached at angle of 45 degrees? c) How much force would a photon receive? d) How big would the gyrations be when an electron encountered the Earth's magnetic field?

Explanation / Answer

1 )

the electron reaches if earth it has got KE

it will follow a decreasing spiral path..

so initial direction will be normal to earth's gravitational force.

2 )

the spiral path is decreasing fast and it reaches the relative early.

3 )

the energy of the particles is E = m c2

m = E / c2

force is = E X g / c2   

4 )

the gyration will be equal to the escape velocity.

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