Shown below are six arrangements of two wooden blocks both moving left to right

Question

Shown below are six arrangements of two wooden blocks both moving left to right at 2 m/s. There are two different moss blocks, either 100 g of 200 g. In all of the arrangements, the blocks arc in contact, that is. they are touching each other. As you can see. one of the blocks given in each arrangement is labeled A. and the other is labeled B. The mass of each block is given in the figures. Rank these arrangements from largest to smallest on the basis of the difference of the strengths (magnitudes) of the forces between the force A exerts on B (FAB) and the force B exerts and A (FBA). In other words, the arrangement where |FAB| In the same way the arrangement where/FAJ - JFBA| is the smallest will rank last. Keep in mind that some of these values might be negative. If FHA is stronger than Fah. then the difference will he negative. Negative values are smaller than positive values or zero.

Explanation / Answer

Newton's third laws of motion states that force Fab from A on body B is equal and opposite to force Fba from b on body A hence |Fab| = |Fba|

which means for all above diagrams  |Fab| - |Fba| = 0.

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