Shown above are six cars of different masses that are moving along horizontal ro

Question

Shown above are six cars of different masses that are moving along horizontal roads at specified speeds. All of the cars are the same size and shape, but they are carrying loads with different masses. All of these cars are going to be stopped by plowing into identical barriers. All of the cars will be stopped by the SAME constant force exerted by the barrier. The speeds and masses of the various cars are shown below according to the corresponding letter.

List the cars in order of increasing stopping distance (from smallest to largest distance).
For example, if B is smallest, then A, C, D, and finally E is largest, enter BACDE.
Note: if equal distance, then enter in the order listed.

Explanation / Answer

here,

distance = kinetic energy/workdone

the force exerted by the barrier is constant

the car having more kinetic energy will have more stoping distance

A)

v = 5 m/s

M = 500 kg

kinetic energy = 0.5 * M * v

kinetic energy = 0.5 * 5^2 * 500

kinetic energy = 6250 J

B)

v = 30 m/s

M = 1500 kg

kinetic energy = 0.5 * M * v

kinetic energy = 0.5 * 30^2 * 1500

kinetic energy = 675000 J

C)

v = 15 m/s

M = 3000 kg

kinetic energy = 0.5 * M * v

kinetic energy = 0.5 * 15^2 * 3000

kinetic energy = 337500 J

D)

v = 35 m/s

M = 3000 kg

kinetic energy = 0.5 * M * v

kinetic energy = 0.5 * 35^2 * 3000

kinetic energy = 1837500 J

E)

v = 35 m/s

M = 1000 kg

kinetic energy = 0.5 * M * v

kinetic energy = 0.5 * 35^2 * 1000

kinetic energy = 612500 J

F)

v = 25 m/s

M = 2500 kg

kinetic energy = 0.5 * M * v

kinetic energy = 0.5 * 25^2 * 2500

kinetic energy = 781250 J

list of car increasing stoping distance is : ACEBFD

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